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POJ2505 A multiplication game[博弈论]
A multiplication game
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 6028 | Accepted: 3013 |
Description
Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p = 1, does his multiplication, then Ollie multiplies the number, then Stan and so on. Before a game starts, they draw an integer 1 < n < 4294967295 and the winner is who first reaches p >= n.
Input
Each line of input contains one integer number n.
Output
For each line of input output one line either
Stan wins.
or
Ollie wins.
assuming that both of them play perfectly.
Stan wins.
or
Ollie wins.
assuming that both of them play perfectly.
Sample Input
1621734012226
Sample Output
Stan wins.Ollie wins.Stan wins.
Source
Waterloo local 2001.09.22
手算一下吧
0~9 stan
10~9*2 ollie //2是Stan，他要尽量阻止Ollie取到n；9是Ollie，他要尽量大来取到n
19~9*2*9 stan
以此类推
可以直接用n不断/18
注意double n
#include<cstdio>double n;int main(){ while(scanf("%lf",&n)!=EOF){ while(n>18) n/=18; if(n<=9) puts("Stan wins."); else puts("Ollie wins."); }}
POJ2505 A multiplication game[博弈论]
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