python 从小到大排序

1.冒泡排序：  O（n2） 

s=[3,4,2,5,1,9]
#count = 0
for i in range(len(s)):
    for j in range((i+1),len(s)):
        s[i],s[j]=min(s[i],s[j]),max(s[i],s[j])
        #print count
print s



2.选择排序： O(n2)

s=[3,4,2,5,1,9]
#count = 0
for i in range(len(s)):
    temp = i
    for j in range(i + 1, len(s)):
        if s[j] < s[temp]:
            temp = j
    if temp != i:
        count += 1
        s[i], s[temp] = s[temp], s[i]
print s
#print count
    

3.插入交换：   O(n2)

s=[3,4,2,5,1,8,0,9]

for i in range (len(s)):
    for j in range(i,0,-1):
        if s[j] < s[j-1]:
            s[j],s[j-1]=s[j-1],s[j]
        else:
            break

print s