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D - Babelfish
Description
You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.
Input
Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.
Output
Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".
Sample Input
dog ogday cat atcay pig igpay froot ootfray loops oopslay atcay ittenkay oopslay
Sample Output
cat eh loops
Hint
Huge input and output,scanf and printf are recommended.
给出每两个字符串,它们代表相同意思的不同语言,给出一种语言的意思,将其转换成另一种语言,如果没有找到,输出“eh”。
解题思路:本题最好采用字典树,估计用时较少,我采用的是二分查找,用时700ms。
代码如下:C/C++代码
#include <stdio.h> #include <string.h> #include <algorithm> using namespace std; struct node { char s1[20],s2[20]; } a[100005]; int cmp(node a,node b) { return strcmp(a.s2,b.s2)<0; } int main() { int i,j,low,mid,high,flag=1,len = 0; char s[50]; while(gets(s)) { if(strlen(s)==0) break; sscanf(s,"%s%s",a[len].s1,a[len].s2); len++; } sort(a,a+len,cmp);//按字典序排序 //二分查找 while(gets(s)) { low=0; high=len-1; flag=1; while(low<=high) { int mid =(low+high)>>1; if(strcmp(s,a[mid].s2)==0) { printf("%s\n",a[mid].s1); flag = 0; break; } else if(strcmp(s,a[mid].s2)>0) low=mid+1; else high=mid-1; } if(flag) printf("eh\n"); } return 0; }
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