1 #include<stdio.h>
 2 long int dog(int p)
 3 {
 4     if(p>1)    
 5         return dog(p-1)+dog(p-2);
 6     else if (p==1||p==0)
 7         return 1;
 8 }
 9 int main()
10 {
11     printf("您要求第几个斐波纳契数：\n");
12     int n;
13     scanf("%d",&n);
14     printf("第%d个斐波纳契数是:\n%ld\n",n,dog(n-1));
15 }