首页 > 代码库 > Leetcode: Design Snake Game
Leetcode: Design Snake Game
Design a Snake game that is played on a device with screen size = width x height. Play the game online if you are not familiar with the game. The snake is initially positioned at the top left corner (0,0) with length = 1 unit. You are given a list of food‘s positions in row-column order. When a snake eats the food, its length and the game‘s score both increase by 1. Each food appears one by one on the screen. For example, the second food will not appear until the first food was eaten by the snake. When a food does appear on the screen, it is guaranteed that it will not appear on a block occupied by the snake. Example: Given width = 3, height = 2, and food = [[1,2],[0,1]]. Snake snake = new Snake(width, height, food); Initially the snake appears at position (0,0) and the food at (1,2). |S| | | | | |F| snake.move("R"); -> Returns 0 | |S| | | | |F| snake.move("D"); -> Returns 0 | | | | | |S|F| snake.move("R"); -> Returns 1 (Snake eats the first food and right after that, the second food appears at (0,1) ) | |F| | | |S|S| snake.move("U"); -> Returns 1 | |F|S| | | |S| snake.move("L"); -> Returns 2 (Snake eats the second food) | |S|S| | | |S| snake.move("U"); -> Returns -1 (Game over because snake collides with border)
HashSet + Queue:
吃东西的时候保留尾巴,不吃的时候删去尾巴
one case to notice蛇转弯的时候,要先删去尾巴,再把新的点加进去。如果这个顺序不对的话,本来不会撞上尾巴的结果会判断会撞上
1 public class SnakeGame { 2 int m; 3 int n; 4 int[][] foods; 5 Queue<Integer> queue; 6 HashSet<Integer> set; 7 int[] headPos; 8 int foodSeq; 9 10 11 /** Initialize your data structure here. 12 @param width - screen width 13 @param height - screen height 14 @param food - A list of food positions 15 E.g food = [[1,1], [1,0]] means the first food is positioned at [1,1], the second is at [1,0]. */ 16 public SnakeGame(int width, int height, int[][] food) { 17 this.m = height; 18 this.n = width; 19 this.foods = food; 20 this.queue = new LinkedList<Integer>(); 21 this.set = new HashSet<Integer>(); 22 this.headPos = new int[]{0, 0}; 23 this.foodSeq = 0; 24 queue.offer(0); 25 set.add(0); 26 } 27 28 /** Moves the snake. 29 @param direction - ‘U‘ = Up, ‘L‘ = Left, ‘R‘ = Right, ‘D‘ = Down 30 @return The game‘s score after the move. Return -1 if game over. 31 Game over when snake crosses the screen boundary or bites its body. */ 32 public int move(String direction) { 33 int[] dir; 34 switch(direction) { 35 case "U": dir = new int[]{-1, 0}; break; 36 case "L": dir = new int[]{0, -1}; break; 37 case "R": dir = new int[]{0, 1}; break; 38 case "D": dir = new int[]{1, 0}; break; 39 default: dir = new int[2]; 40 } 41 int row = headPos[0] + dir[0]; // new position row 42 int col = headPos[1] + dir[1]; // new position col 43 44 //delete tail first, before push into a new cell 45 if (foodSeq<foods.length && calcPosId(foods[foodSeq][0], foods[foodSeq][1]) == calcPosId(row, col)) { 46 foodSeq++; 47 } 48 else { 49 set.remove(queue.poll()); 50 } 51 52 if (row<0 || row>=m || col<0 || col>=n) return -1; // hit border 53 if (set.contains(calcPosId(row, col))) return -1; // hit its own body 54 55 set.add(calcPosId(row, col)); 56 queue.offer(calcPosId(row, col)); 57 headPos[0] = row; 58 headPos[1] = col; 59 60 return set.size()-1; 61 } 62 63 public int calcPosId(int x, int y) { 64 return x*n+y; 65 } 66 } 67 68 /** 69 * Your SnakeGame object will be instantiated and called as such: 70 * SnakeGame obj = new SnakeGame(width, height, food); 71 * int param_1 = obj.move(direction); 72 */
如果没有39行,程序会说dir没有initialize,
其实更好的写法应该是
1 int rowHead = body.peekFirst() / width; 2 int colHead = body.peekFirst() % width; 3 switch (direction) { 4 case "U" : rowHead--; 5 break; 6 case "D" : rowHead++; 7 break; 8 case "L" : colHead--; 9 break; 10 default : colHead++; 11 }
Leetcode: Design Snake Game
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。