一、点修改:二、区间修改:(1)区间中每点值直接修改为v。sum = 0;ma = 0;mi = INT_INF;query(x, y, 1, 1, N);代码如下:int sumv[MAXN << 2], maxv[MAXN << 2
https://www.u72.net/daima/7mur.html - 2024-09-11 00:29:22 - 代码库对于一个图,n个节点,有向边,求点s到其他所有点的最短路。题目给的边的方式:u -> v[l,r] -> vv -> [l,r]这样的话边数是O(n^2)级别的,怎么做?假设把[1,n
https://www.u72.net/daima/8a75.html - 2024-09-11 02:39:03 - 代码库DescriptionYou have N integers, A1, A2, ... ,AN. You need to deal with two kinds of operations. One type of operation is to add some given
https://www.u72.net/daima/970w.html - 2024-09-14 05:03:36 - 代码库一、索引分裂1. 什么是分裂在开始介绍之前,我们先来搞清楚什么是索引分裂吧。“索引分裂”就是索引块的分裂,当一次DML事务操作修改了索引块上的数据,
https://www.u72.net/daima/92v5.html - 2024-09-13 21:10:40 - 代码库1 //s d s 2 #include<cstdio> 3 #include<iostream> 4 #include<cstdlib> 5 using namespace std; 6 const int N=5000006; 7 long long a[N
https://www.u72.net/daima/nnwfm.html - 2024-09-20 13:14:50 - 代码库<select id="cc" style="width: 250px"></select> <div id="sp"> <div style="color: #99BBE8; background: #faf
https://www.u72.net/daima/9hbh.html - 2024-07-27 03:55:15 - 代码库Encoded BarcodesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1644 Accepted Su
https://www.u72.net/daima/9vks.html - 2024-07-27 12:11:17 - 代码库★ 输入文件:treed.in 输出文件:treed.out 简单对比时间限制:1 s 内存限制:128 MB【问题描述】在一个凉爽的夏夜,xth和rabbit来到花园里砍树。为啥
https://www.u72.net/daima/9vsk.html - 2024-09-13 13:20:31 - 代码库http://www.lintcode.com/zh-cn/problem/segment-tree-build/注意点: 根节点用root表示 把start == end的判断和后面代码合并,可以少一次return
https://www.u72.net/daima/na6kz.html - 2024-09-19 07:41:06 - 代码库sum表示节点的和max表示节点的最大&#20540;lsum表示节点从左边开始的最大&#20540;rsum表示节点从右边开始的最大&#20540;You are given a sequence A[1
https://www.u72.net/daima/eh3c.html - 2024-07-28 05:14:31 - 代码库链接:http://acm.hdu.edu.cn/showproblem.php?pid=3911题意:给出01串 1代表黑色 0代表白色 0 a b:询问[a,b]中1的连续最大长度 1 a,b:把[a,b]区间
https://www.u72.net/daima/eab6.html - 2024-09-14 12:13:34 - 代码库http://codevs.cn/problem/1080/#include <vector>#include <iostream>#include <string.h>using namespace std;const int MAXN = 100000;struct Line
https://www.u72.net/daima/99ud.html - 2024-07-27 23:30:38 - 代码库1.洛谷p1351 https://www.luogu.org/problem/show?pid=1531//单点修改区间询问 #include<iostream>#include<cstdio>#include<cstring>#define maxn 20
https://www.u72.net/daima/nnkb9.html - 2024-09-19 23:11:44 - 代码库import java.util.ArrayList;import java.util.Queue;import java.util.LinkedList;/**public class TreeNode { int val = 0; TreeNode
https://www.u72.net/daima/nnh78.html - 2024-09-19 22:32:05 - 代码库链接:http://poj.org/problem?id=2182题意:有N头牛,编号1~N,乱序排成一列,现在已知每头牛前面有多少头牛比它的编号小,求排队后从前往后数,每头牛的编号题解:从
https://www.u72.net/daima/nada9.html - 2024-09-18 06:40:09 - 代码库题目描述如题,已知一个数列,你需要进行下面两种操作:1.将某区间每一个数加上x2.求出某区间每一个数的和输入输出格式输入格式:第一行包含两个整数N
https://www.u72.net/daima/nabbb.html - 2024-09-18 08:32:16 - 代码库#include<iostream>#include<cstdio>#include<cstring>#include<stack>#include<queue>#include<algorithm>const int maxn=1007;const int IN
https://www.u72.net/daima/effr.html - 2024-09-14 22:59:10 - 代码库Problem Description:N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到
https://www.u72.net/daima/eb0n.html - 2024-09-14 21:52:13 - 代码库Mart Master IITime Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 285 Accepted Subm
https://www.u72.net/daima/navvz.html - 2024-07-30 16:19:04 - 代码库Prim算法:算法实现的原理 同Dijkstra类&#20284;,都是以某个顶点出发,只不过是添加边的集合。简单描述:1).输入:一个加权连通图,其中顶点集合为V,边集合为E;2).
https://www.u72.net/daima/navex.html - 2024-07-30 16:50:01 - 代码库