首页 > 代码库 > hdu 3125 Slash（模拟）

hdu 3125 Slash（模拟）

2024-07-17 22:58:50   215人阅读

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=3125



Problem Description
The American English slash (/) is a punctuation mark. In the early modern period, in the Fraktur script, which was widespread through Europe in the Middle Ages, one slash(/) represented a comma, while two slashes (//) represented a dash.
With the wide use of computers, slash appeared far more than at any previous time in history. On Unix-like systems and in URLs, the slash is to separate directory and file components of a path:
/home/whuacm/chaeyeon/Sherlockpp.jpg
http://acm.whu.edu.cn/
But in Windows systems, it uses (\) to separate directory and file components of a path:
C:\Users\v-yungao\Music\Shake
That really confuses me. Could you help me to judge if the string I wrote is right. 
Please notice that I would only make a mistake by changing (\) to (/) or (/) to (\). All the strings were constituted by a-z, A-Z, 0-9, (.) , (\) and (/), no other characters would appear in the strings.
A string of URL always begins with “[a-zA-Z]+://” (Notice (/) maybe changed to (\) ), in which “[a-zA-Z]+” represents any non-empty string of letters.
Windows path begins with “[a-zA-Z]:\” (Notice (\) maybe changed to (/)), in which “[a-zA-Z]” means an English letter. (e.g. “C:\\windows” is a URL not a Windows path)
The path of Unix-like system begins with (/) or (\).
I’ll give you some strings, can you tell me which type those strings belong to and those correct forms.
 

Input
The first line consists of an integer T, indicating the number of strings.
The next T lines, each line consists of a single non-empty string. All of those are really data from our daily life. 
 

Output
For each string:
If it belongs to a path in Unix-like systems, output “It’s a path in Unix-like systems!” in a new line and the correct string in the next line.
If it belongs to a path in Windows system, output “It’s a path in Windows system!” in a new line and the correct string in the next line.
If it’s a URL, output “It’s a URL!” in a new line and the correct string in the next line.
The kind of each input string can be uniquely determined. 

Constrains
0 < T <= 20
The length of each string will not be longer than 50.

 

Sample Input
4
http://acm.whu.edu.cn/felioj
http:/\acm.whu.edu.cn/11111011001/
\home\whuacm\Slash\yama
Z:\movie/chaeyeon
 

Sample Output
It‘s a URL!
http://acm.whu.edu.cn/felioj
It‘s a URL!
http://acm.whu.edu.cn/11111011001/
It‘s a path in Unix-like systems!
/home/whuacm/Slash/yama
It‘s a path in Windows system!
Z:\movie\chaeyeon
 

Source
2009 Asia Wuhan Regional Contest Online


代码如下：

//#pragma warning (disable:4786)
#include <cstdio>
#include <cmath>
#include <cstring>
#include <string>
#include <cstdlib>
#include <climits>
#include <ctype.h>
#include <queue>
#include <stack>
#include <vector>
#include <utility>
#include <deque>
#include <set>
#include <map>
#include <iostream>
#include <algorithm>
using namespace std;
const double eps = 1e-9;
//const double pi = atan(1.0)*4;
const double pi = 3.1415926535897932384626;
#define INF 1e18
//typedef long long LL;
//typedef __int64 LL;

bool Judge(char c)
{
    if(c == '/' || c == '\\')
        return true;
    return false;
}
int main()
{
    int t;
    char str[57];
    scanf("%d",&t);
    while(t--)
    {
        memset(str,'\0',sizeof(str));
        scanf("%s",str);
        int len = strlen(str);
        if(Judge(str[0]))
        {
            printf("It's a path in Unix-like systems!\n");
            for(int j = 0; j < len; j++)
            {
                if(str[j] == '\\')
                    printf("/");
                else
                    printf("%c",str[j]);
            }
            printf("\n");
            continue;
        }
        for(int i = 0; i < len; i++)
        {

            if(Judge(str[i]) && Judge(str[i+1]))
            {
                printf("It's a URL!\n");
                for(int j = 0; j < len; j++)
                {
                    if(str[j] == '\\')
                        printf("/");
                    else
                        printf("%c",str[j]);
                }
                printf("\n");
                break;
            }
            else if(Judge(str[i]))
            {
                printf("It's a path in Windows system!\n");
                for(int j = 0; j < len; j++)
                {
                    if(str[j] == '/')
                        printf("\\");
                    else
                        printf("%c",str[j]);
                }
                printf("\n");
                break;
            }
        }
    }
    return 0;
}



联系
我们