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HDU5477(模拟)

2024-08-13 07:05:30   218人阅读

A Sweet Journey

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 975    Accepted Submission(s): 504


Problem Description

Master Di plans to take his girlfriend for a travel by bike. Their journey, which can be seen as a line segment of length L, is a road of swamps and flats. In the swamp, it takes A point strengths per meter for Master Di to ride; In the flats, Master Di will regain B point strengths per meter when riding. Master Di wonders：In the beginning, he needs to prepare how much minimum strengths. (Except riding all the time,Master Di has no other choice) 

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Input

In the first line there is an integer t (1≤t≤50), indicating the number of test cases.
For each test case:
The first line contains four integers, n, A, B, L.
Next n lines, each line contains two integers: Li,Ri, which represents the interval [Li,Ri] is swamp.
1≤n≤100,1≤L≤105,1≤A≤10,1≤B≤10，1≤Li<Ri≤L.
Make sure intervals are not overlapped which means Ri<Li+1 for each i (1≤i<n).
Others are all flats except the swamps.
 

 

Output

For each text case:
Please output “Case #k: answer”(without quotes) one line, where k means the case number counting from 1, and the answer is his minimum strengths in the beginning.
 

 

Sample Input

1
2 2 2 5
1 2
3 4
 

 

Sample Output

Case #1: 0
 

 

Source

2015 ACM/ICPC Asia Regional Shanghai Online
 
 1 //2016.9.13 2 #include <iostream> 3 #include <cstdio> 4 #define N 105 5  6 using namespace std; 7  8 int main() 9 {10     int T, kase = 0, ans, n, a, b, len, l[N], r[N];11     scanf("%d", &T);12     while(T--)13     {14         int tmp = 0;15         ans = 0;//假设最初需要0点能量16         scanf("%d%d%d%d", &n, &a, &b, &len);17         l[0] = r[0] = 0;18         for(int i = 1; i <= n; i++)19         {20             scanf("%d%d", &l[i], &r[i]);21             tmp = tmp+b*(l[i]-r[i-1])-a*(r[i]-l[i]);22             if(ans > tmp)ans = tmp;23         }24         printf("Case #%d: %d\n", ++kase, -ans);25     }26 27     return 0;28 }

 

HDU5477(模拟)


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