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UVA - 297 Quadtrees (四分树)
题意:求两棵四分树合并之后黑色像素的个数。
分析:边建树边统计。
#include<cstdio> #include<cstring> #include<cstdlib> #include<cctype> #include<cmath> #include<iostream> #include<sstream> #include<iterator> #include<algorithm> #include<string> #include<vector> #include<set> #include<map> #include<stack> #include<deque> #include<queue> #include<list> typedef long long ll; typedef unsigned long long llu; const int INT_INF = 0x3f3f3f3f; const int INT_M_INF = 0x7f7f7f7f; const ll LL_INF = 0x3f3f3f3f3f3f3f3f; const ll LL_M_INF = 0x7f7f7f7f7f7f7f7f; const int dr[] = {0, 0, -1, 1}; const int dc[] = {-1, 1, 0, 0}; const double pi = acos(-1.0); const double eps = 1e-8; const int MAXN = 1100 + 10; const int MAXT = 40 + 10; using namespace std; char s[MAXN]; int vis[MAXT][MAXT]; int cnt; void dfs(int &id, int r, int c, int len){ char cc = s[id++];//传参加自增,遍历每个元素 if(cc == ‘p‘){ dfs(id, r, c + len / 2, len / 2);//1 dfs(id, r, c, len / 2);//2 dfs(id, r + len / 2, c, len / 2);//3 dfs(id, r + len / 2, c + len / 2, len / 2);//4 } else if(cc == ‘f‘){ for(int i = r; i < r + len; ++i){ for(int j = c; j < c + len; ++j){ if(!vis[i][j]){ vis[i][j] = 1; ++cnt; } } } } } int main(){ int T; scanf("%d", &T); while(T--){ memset(vis, 0, sizeof vis); cnt = 0; for(int i = 0; i < 2; ++i){ scanf("%s", s); int id = 0; dfs(id, 0, 0, 32); } printf("There are %d black pixels.\n", cnt); } return 0; }
UVA - 297 Quadtrees (四分树)
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