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HDU 3726 Graph and Queries treap树
题目来源:HDU 3726 Graph and Queries
题意:见白书
思路:刚学treap 参考白皮书
#include <cstdio> #include <cstring> #include <cstdlib> using namespace std; struct Node { Node *ch[2]; int r; int v; int s; Node(int v): v(v) { ch[0] = ch[1] = NULL; r = rand(); s = 1; } bool operator < (const Node& rhs) const{ return r < rhs.r; } int cmp(int x) const{ if(x == v) return -1; return x < v ? 0 : 1; } void maintain(){ s = 1; if(ch[0] != NULL) s += ch[0]->s; if(ch[1] != NULL) s += ch[1]->s; } }; void rotate(Node* &o, int d){ Node* k = o->ch[d^1]; o->ch[d^1] = k->ch[d]; k->ch[d] = o; o->maintain(); k->maintain(); o = k; } void insert(Node* &o, int x){ if(o == NULL){ o = new Node(x); } else{ int d = (x < o->v ? 0 : 1); insert(o->ch[d], x); if(o->ch[d] > o) rotate(o, d^1); } o->maintain(); //printf("--------+%d\n", o->s); } void remove(Node* &o, int x){ int d = o->cmp(x); if(d == -1){ Node* u = o; if(o->ch[0] != NULL && o->ch[1] != NULL){ int d2 = o->ch[0] > o->ch[1] ? 1 : 0; rotate(o, d2); remove(o->ch[d2], x); } else{ if(o->ch[0] == NULL) o = o->ch[1]; else o = o->ch[0]; delete u; } } else remove(o->ch[d], x); if(o != NULL) o->maintain(); }
HDU 3726 Graph and Queries treap树
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