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485. 找出二进制串中连续的1的个数 Max Consecutive Ones


Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

找出一个二进制串中连续的1的个数。


  1. static public int FindMaxConsecutiveOnes(int[] nums) {
  2. if (nums.Length == 0) {
  3. return 0;
  4. }
  5. int maxNumber = 0;
  6. int number = 0;
  7. for (int i = 0; i <= nums.Length; i++) {
  8. if (i != nums.Length && nums[i] == 1) {
  9. number++;
  10. } else {
  11. if (number > maxNumber) {
  12. maxNumber = number;
  13. }
  14. number = 0;
  15. }
  16. }
  17. return maxNumber;
  18. }



来自为知笔记(Wiz)


485. 找出二进制串中连续的1的个数 Max Consecutive Ones