首页 > 代码库 > 485. Max Consecutive Ones (最大连续数) by Python

485. Max Consecutive Ones (最大连续数) by Python

485. Max Consecutive Ones

题目:

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

 

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

给你一个二位数列表,求出列表最大的1连续的数目

思路:

很简单的列表遍历,要注意的就是最后一次遍历的值也要进行比较

 

结果:

class Solution(object):
def findMaxConsecutiveOnes(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
max_num = 0
statistics = 0
# 遍历列表
for temp in nums:
if temp == 1:
statistics += 1
else:
if statistics > max_num:
max_num = statistics
statistics = 0
# 保证最后一遍也能进行比较
if statistics > max_num:
max_num = statistics
return max_num

485. Max Consecutive Ones (最大连续数) by Python