首页 > 代码库 > N-Queens
N-Queens
The n-queens puzzle is the problem of placing n queens on ann×n chessboard such that no two queens attack each other.
Given an integer n, return all distinct solutions to the n-queens puzzle.
Each solution contains a distinct board configuration of the n-queens‘ placement, where‘Q‘
and ‘.‘
both indicate a queen and an empty space respectively.
For example,
There exist two distinct solutions to the 4-queens puzzle:
[ [".Q..", // Solution 1 "...Q", "Q...", "..Q."], ["..Q.", // Solution 2 "Q...", "...Q", ".Q.."] ]
答案
public class Solution { int queenPosition[]; int N; List<String[]>resultList; StringBuilder line; Set<Integer> getRemainingPosition(int index){ Set<Integer> result=new HashSet<Integer>(); int i,j; for(i=0;i<N;i++){ result.add(i); } for(i=0;i<N;i++){ for(j=0;j<index;j++){ if((i==queenPosition[j])||(Math.abs(i-queenPosition[j])==Math.abs(index-j))){ result.remove(i); break; } } } return result; } public void calNQueens(int index) { Set<Integer> remainingPosition=getRemainingPosition(index); if(index+1==N){ for(Integer position:remainingPosition) { queenPosition[index]=position; String []result=new String[N]; for(int i=0;i<N;i++) { line.setCharAt(queenPosition[i],'Q'); result[i]=line.toString(); line.setCharAt(queenPosition[i],'.'); } resultList.add(result); } } else { for(Integer position:remainingPosition) { queenPosition[index]=position; calNQueens(index+1); } } } public List<String[]> solveNQueens(int n) { N=n; resultList=new LinkedList<String[]>(); queenPosition=new int[N]; line=new StringBuilder(N); for(int i=0;i<N;i++) { line.append("."); } calNQueens(0); return resultList; } }
N-Queens
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。