首页 > 代码库 > HDU 1002-A + B Problem II(大数类)
HDU 1002-A + B Problem II(大数类)
A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 215173 Accepted Submission(s): 41521
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2 1 2 112233445566778899 998877665544332211
Sample Output
Case 1: 1 + 2 = 3 Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110BigInteger 一水。import java.io.*; import java.util.*; import java.math.*; public class Main { public static void main(String[] args){ Scanner in=new Scanner(System.in); BigInteger a,b;int n,cas=1; n=in.nextInt(); for(int i=0;i<n;i++){ a=in.nextBigInteger(); b=in.nextBigInteger(); System.out.println("Case "+cas+":"); ++cas; System.out.println(a+" + "+b+" = "+a.add(b)); if(i!=n-1) System.out.println(""); } } }
HDU 1002-A + B Problem II(大数类)
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。