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后缀数组 - 求最长公共子序列 + 模板题 : poj 2774

// Memory   Time// 1347K     0MS// by : Snarl_jsb// 2014-09-24-19.57#include<algorithm>#include<cstdio>#include<cstring>#include<cstdlib>#include<iostream>#include<vector>#include<queue>#include<stack>#include<map>#include<string>#include<climits>#include<cmath>#define N 100050<<1#define LL long longusing namespace std;int num[N];char str[N];namespace Suf{    int sa[N], rank[N], height[N];    int wa[N], wb[N], wv[N], wd[N];    int cmp(int *r, int a, int b, int l)    {        return r[a] == r[b] && r[a+l] == r[b+l];    }    void da(int *r, int n, int m)     //    参数:*r---str转化为int型后的数组  n----数组长度  m---元素的范围    {        int i, j, p, *x = wa, *y = wb, *t;        for(i = 0; i < m; i ++) wd[i] = 0;        for(i = 0; i < n; i ++) wd[x[i]=r[i]] ++;        for(i = 1; i < m; i ++) wd[i] += wd[i-1];        for(i = n-1; i >= 0; i --) sa[-- wd[x[i]]] = i;        for(j = 1, p = 1; p < n; j *= 2, m = p)        {            for(p = 0, i = n-j; i < n; i ++) y[p ++] = i;            for(i = 0; i < n; i ++) if(sa[i] >= j) y[p ++] = sa[i] - j;            for(i = 0; i < n; i ++) wv[i] = x[y[i]];            for(i = 0; i < m; i ++) wd[i] = 0;            for(i = 0; i < n; i ++) wd[wv[i]] ++;            for(i = 1; i < m; i ++) wd[i] += wd[i-1];            for(i = n-1; i >= 0; i --) sa[-- wd[wv[i]]] = y[i];            for(t = x, x = y, y = t, p = 1, x[sa[0]] = 0, i = 1; i < n; i ++)                x[sa[i]] = cmp(y, sa[i-1], sa[i], j) ? p - 1 : p ++;        }    }    void calcHeight(int *r, int n)         //  求height数组    {        int i, j, k = 0;        for(i = 1; i <= n; i ++) rank[sa[i]] = i;        for(i = 0; i < n; height[rank[i ++]] = k)        {            for(k ? k -- : 0, j = sa[rank[i]-1]; r[i+k] == r[j+k]; k ++);        }    }}using namespace Suf;int main(){    ios_base::sync_with_stdio(false);    cin.tie(0);//    freopen("C:\\Users\\ASUS\\Desktop\\cin.cpp","r",stdin);//    freopen("C:\\Users\\ASUS\\Desktop\\cout.cpp","w",stdout);    gets(str);    int len1=strlen(str);    for(int i=0;i<len1;++i)        num[i]=str[i]-‘a‘+2;    num[len1]=1;    gets(str);    int len2=strlen(str);    for(int i=0;i<len2;++i)        num[i+len1+1]=str[i]-‘a‘+2;    int n=len1+len2;    da(num,n+1,30);    calcHeight(num,n);    int ans=0;    for(int i=2;i<n;++i)    {        if((sa[i] < len1 && sa[i-1] > len1) || (sa[i-1] < len1 && sa[i] > len1))    //判断是否属于不同的两个串            ans=max(ans,height[i]);    }    cout<<ans<<endl;    return 0;}

  

后缀数组 - 求最长公共子序列 + 模板题 : poj 2774