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HDU 5055 Bob and math problem(构造)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5055
Problem Description
Recently, Bob has been thinking about a math problem.
There are N Digits, each digit is between 0 and 9. You need to use this N Digits to constitute an Integer.
This Integer needs to satisfy the following conditions:
Example:
There are three Digits: 0, 1, 3. It can constitute six number of Integers. Only "301", "103" is legal, while "130", "310", "013", "031" is illegal. The biggest one of odd Integer is "301".
There are N Digits, each digit is between 0 and 9. You need to use this N Digits to constitute an Integer.
This Integer needs to satisfy the following conditions:
- 1. must be an odd Integer.
- 2. there is no leading zero.
- 3. find the biggest one which is satisfied 1, 2.
Example:
There are three Digits: 0, 1, 3. It can constitute six number of Integers. Only "301", "103" is legal, while "130", "310", "013", "031" is illegal. The biggest one of odd Integer is "301".
Input
There are multiple test cases. Please process till EOF.
Each case starts with a line containing an integer N ( 1 <= N <= 100 ).
The second line contains N Digits which indicate the digit $a_1, a_2, a_3, \cdots, a_n. ( 0 \leq a_i \leq 9)$.
Each case starts with a line containing an integer N ( 1 <= N <= 100 ).
The second line contains N Digits which indicate the digit $a_1, a_2, a_3, \cdots, a_n. ( 0 \leq a_i \leq 9)$.
Output
The output of each test case of a line. If you can constitute an Integer which is satisfied above conditions, please output the biggest one. Otherwise, output "-1" instead.
Sample Input
3 0 1 3 3 5 4 2 3 2 4 6
Sample Output
301 425 -1
Source
BestCoder Round #11 (Div. 2)
官方题解:
代码如下:
#include <cstdio> #include <cstring> #include <algorithm> using namespace std; int main() { int n; int a[117]; while(~scanf("%d",&n)) { int minn = 10; int flag = 0; int tt = 0; for(int i = 0; i < n; i++) { scanf("%d",&a[i]); if(a[i]&1) { flag = 1; if(a[i] < minn) { minn = a[i]; tt = i; } } } a[tt] = 10; sort(a,a+n); if(!flag) { printf("-1\n"); continue; } flag = 0; for(int i = n-2; i >= 0; i--) { if(a[i]==0 && !flag) continue; flag = 1; printf("%d",a[i]); } if(flag || n==1) printf("%d\n",minn); else printf("-1\n"); } return 0; }
HDU 5055 Bob and math problem(构造)
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