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Max Points on a Line
Max Points on a Line
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.
c++版本：
/** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solution { public: int maxPoints(vector<Point> &points) { // IMPORTANT: Please reset any member data you declared, as // the same Solution instance will be reused for each test case. unordered_map<float,int> mp; int maxNum = 0; for(int i = 0; i < points.size(); i++) { mp.clear(); mp[INT_MIN] = 0; int duplicate = 1; for(int j = 0; j < points.size(); j++) { if(j == i) continue; if(points[i].x == points[j].x && points[i].y == points[j].y) { duplicate++; continue; } float k = points[i].x == points[j].x ? INT_MAX : (float)(points[j].y - points[i].y)/(points[j].x - points[i].x); mp[k]++; } unordered_map<float, int>::iterator it = mp.begin(); for(; it != mp.end(); it++) if(it->second + duplicate > maxNum) maxNum = it->second + duplicate; } return maxNum; } }; java版本：
/** * Definition for a point. * class Point { * int x; * int y; * Point() { x = 0; y = 0; } * Point(int a, int b) { x = a; y = b; } * } */public class Solution{ public int maxPoints(Point[] points) { if(points.length == 0 || points == null) return 0; if(points.length == 1) return 1; int max = 1; for(int i = 0; i < points.length; i++){ int same = 0; int localmax = 1; HashMap<Float, Integer> fm = new HashMap<Float, Integer>(); for(int j = 0; j < points.length; j++) { if(i == j) continue; if(points[i].x == points[j].x && points[i].y == points[j].y) { same ++; continue; } float slop = ((float)(points[i].x - points[j].x)/(points[i].y - points[j].y)); if(fm.containsKey(slop)) fm.put(slop, fm.get(slop) + 1); else fm.put(slop, 2); } for(Integer value : fm.values()) localmax = Math.max(localmax, value); localmax += same; max = Math.max(max,localmax); } return max; }}
Max Points on a Line
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