首页 > 代码库 > 404. Sum of Left Leaves
404. Sum of Left Leaves
Find the sum of all left leaves in a given binary tree.
Example:
3 / 9 20 / 15 7There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
Hide Company Tags
Show Tags
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution { int sum = 0; public int sumOfLeftLeaves(TreeNode root) { if(root == null) return 0; return getleft(root, false); } public int getleft(TreeNode root, boolean isLeft){ if(root == null) return 0; if(root.left == null && root.right == null && isLeft) return root.val; return getleft(root.left ,true) + getleft(root.right, false); }}
404. Sum of Left Leaves
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。