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HDU2516-取石子游戏

2024-07-10 22:41:58   228人阅读

取石子游戏

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2640    Accepted Submission(s): 1503


Problem Description
1堆石子有n个,两人轮流取.先取者第1次可以取任意多个，但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍。取完者胜.先取者负输出"Second win".先取者胜输出"First win".
 

Input
输入有多组.每组第1行是2<=n<2^31. n=0退出.
 

Output
先取者负输出"Second win". 先取者胜输出"First win".
参看Sample Output.
 

Sample Input
2
13
10000
0
 

Sample Output
Second win
Second win
First win
 

Source
ECJTU 2008 Autumn Contest
 

打表找规律，规律为斐波那契数列

#include <iostream>
#include <cstdio>
#include <cstring>
#include <vector>
#include <string>
#include <algorithm>
#include <queue>
#include <set>
using namespace std;
int n;
set<int>fib;
int main(){

    long long a=2,b=3,c=5;
    fib.insert(2);
    fib.insert(3);
    long long end = (1<<31)-1;
    //cout<<end<<endl;
    while(c <= end){
        fib.insert(c);
        a = b;
        b = c;
        c = a+b;
    }
    while(cin >> n && n){
        if(fib.count(n)==0){
            cout<<"First win"<<endl;
        }else{
            cout<<"Second win"<<endl;
        }
    }
    return 0;
}



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