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UVa 11040 Add bricks in the wall (水题递推)

题意:给定一个金字塔,除了最后一行,每个数都等于支撑它的两个数的和,现在给奇数行的左数奇数位置,求整个金字塔。

析:很容易看出来,从下往上奇数行等于 a[i][j] = (a[i-2][j-1] - a[i][j-1] - a[i][j+1]) / 2;然后偶数行就推出来了。

代码如下:

#pragma comment(linker, "/STACK:1024000000,1024000000")#include <cstdio>#include <string>#include <cstdlib>#include <cmath>#include <iostream>#include <cstring>#include <set>#include <queue>#include <algorithm>#include <vector>#include <map>#include <cctype>#include <cmath>#include <stack>#define print(a) printf("%d\n", (a))#define freopenr freopen("in.txt", "r", stdin)#define freopenw freopen("out.txt", "w", stdout)using namespace std;typedef long long LL;typedef pair<int, int> P;const int INF = 0x3f3f3f3f;const double inf = 0x3f3f3f3f3f3f;const LL LNF = 0x3f3f3f3f3f3f;const double PI = acos(-1.0);const double eps = 1e-8;const int maxn = 1e3 + 5;const int mod = 1e9 + 7;const int dr[] = {-1, 0, 1, 0};const int dc[] = {0, 1, 0, -1};const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};int n, m;const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};inline int Min(int a, int b){ return a < b ? a : b; }inline int Max(int a, int b){ return a > b ? a : b; }inline LL Min(LL a, LL b){ return a < b ? a : b; }inline LL Max(LL a, LL b){ return a > b ? a : b; }inline bool is_in(int r, int c){    return r >= 0 && r < n && c >= 0 && c < m;}int a[15][15];int main(){    cin >> n;    while(n--){        memset(a, 0, sizeof(a));        for(int i = 1; i < 10; i += 2)            for(int j = 1; j <= i; j += 2)                cin >> a[i][j];        for(int i = 1; i < 10; i++)            for(int j = 2; j <= i; j++)                if(!a[i][j])    a[i][j] = (a[i-2][j-1] - a[i][j-1] - a[i][j+1]) / 2;        for(int i = 2; i < 9; i += 2)            for(int j = 1; j <= i; j++)                a[i][j] = a[i+1][j] + a[i+1][j+1];        for(int i = 1; i < 10; i++)            for(int j = 1; j <= i; j++)                if(j == i)      printf("%d\n", a[i][j]);                else            printf("%d ", a[i][j]);    }    return 0;}

 

UVa 11040 Add bricks in the wall (水题递推)