首页 > 代码库 > 经典图算法Java代码实践:BFS,DFS以及几种最短路径算法
经典图算法Java代码实践:BFS,DFS以及几种最短路径算法
public class City { String name; int id; static int idCounter = 0; public City(String name) { this.name=name; id = idCounter++; } }
import java.util.ArrayList; public class Graph { public static void main(String[] args) { // TODO Auto-generated method stub Map M = new Map(12); City a = new City("a"); City b = new City("b"); City c = new City("c"); City d = new City("d"); City e = new City("e"); City f = new City("f"); City g = new City("g"); City h = new City("h"); City i = new City("i"); City j = new City("j"); City k = new City("k"); City l = new City("l"); M.createEdge(a,b,3); M.createEdge(a,c,5); M.createEdge(a,d,4); M.createEdge(b,f,6); M.createEdge(c,d,2); M.createEdge(c,g,4); M.createEdge(d,e,1); M.createEdge(d,h,5); M.createEdge(e,f,2); M.createEdge(e,i,4); M.createEdge(f,j,5); M.createEdge(g,h,3); M.createEdge(g,k,6); M.createEdge(h,i,6); M.createEdge(h,k,7); M.createEdge(i,j,3); M.createEdge(i,l,5); M.createEdge(j,l,9); M.createEdge(k,l,8); System.out.println("the graph is:\n"); System.out.println(M); System.out.println(); System.out.println("findPathByDFS:a to k"); M.findPathByDFS(a,k); System.out.println(); System.out.println("findPathByBFS:a to k"); M.findPathByBFS(a,k); System.out.println(); System.out.println("bellmanFord from a:"); M.bellmanFord(a); System.out.println(); System.out.println("dijkstra from a:"); M.dijkstra(a); System.out.println(); System.out.println("bellmanFord,print example from a:"); M.floydWarshall(); M.printFloydWarshallForOneCity(a); } }
import java.util.ArrayList; import java.util.LinkedList; import java.util.Queue; public class Map { double[][] A; public Map(int n) { A = new double[n][n]; for(int i = 0;i < A.length;i++) { for(int j = 0;j < A.length;j++) { if(i == j) A[i][j] = 0; else A[i][j] = -1; } } } ArrayList<City> cities = new ArrayList<City>(); private double[] D; private void relax(int u,int v) { if(D[v]>D[u]+A[v][u]) D[v]=D[u]+A[v][u]; } private double[][] DD = null; public void floydWarshall() { DD = new double[A.length][A.length]; int i,j,k; for(i = 0;i < A.length;i++) { for(j = 0;j < A.length;j++) { if(A[i][j]>0) DD[i][j] = A[i][j]; else if(i == j) DD[i][j] = 0; else DD[i][j] = 99999999; } } for(k = 0;k < A.length;k++) for(i = 0;i < A.length;i++) for(j = 0;j < A.length;j++) { if(DD[i][j] > DD[i][k] + DD[k][j]) { DD[i][j] = DD[i][k] + DD[k][j]; } } } public void printFloydWarshallForOneCity(City city) { System.out.println("floydWarshall:"); if(DD == null) { floydWarshall(); } for(int i=0;i<A.length;i++) { System.out.printf("from %s to %s shortest path is:%f\n",city.name,cities.get(i).name,DD[city.id][i]); } } public void dijkstra(City city) { dijkstra(city.id); System.out.println("dijkstra:"); for(int i=0;i<A.length;i++) { System.out.printf("from %s to %s shortest path is:%f\n", city.name,cities.get(i).name,D[i]); } } public void dijkstra(int srcId) { D = new double[A.length]; for(int i=0;i<A.length;i++) { D[i]=999999999; } D[srcId]=0; int[] q = new int[A.length]; int ql=0,qf=0; //队列 for(int i=0;i<A.length;i++) q[ql++]=i; while(qf!=ql) { int min=qf; for(int i=qf;i<ql;i++) { if(D[q[i]]<D[q[min]]) { min=i; } } int id = q[qf]; q[qf] = q[min]; q[min] = id; //q[qf] is the min int u=q[qf++]; for(int i=0;i<A.length;i++) { if(A[u][i]>0) { relax(u,i); } } } } public void bellmanFord(City city) { bellmanFord(city.id); System.out.println("bellmanFord:"); for(int i=0;i<A.length;i++) { System.out.printf("from %s to %s shortest path is:%f\n", city.name,cities.get(i).name,D[i]); } } public void bellmanFord(int srcId) { D = new double[A.length]; for(int i=0;i<A.length;i++) { D[i] = 99999999;//无穷大 } D[srcId] = 0; for(int i=0;i<A.length;i++)//外层循环次数 { for(int j=0;j<A.length;j++) { for(int k=0;k<A.length;k++) { if(A[j][k]>0) { relax(j,k); } } } } } Queue<Integer> bfsQueue = new LinkedList<Integer>(); boolean[] bfsFlag; int bsfPre[]; public void findPathByBFS(City src,City dst) { System.out.printf("bfs find path between '%s' and '%s'!\n",src.name,dst.name); findPathByBFS( src.id, dst.id); printBFS(dst.id); } public void findPathByBFS(int srcId,int dstId) { bsfPre = new int[A.length]; bfsQueue.clear(); bfsFlag = new boolean[A.length]; for(int i=0;i<A.length;i++) { bfsFlag[i] = false; bsfPre[i] = -1; } bfsQueue.offer(srcId); bfsFlag[srcId] = true; while(!bfsQueue.isEmpty()) { int current = bfsQueue.poll(); for(int index=0;index<A.length;index++) { if(current == index) continue; if(A[current][index]>0) //两者相连 { if(index == dstId)//找到目标了 { bfsFlag[index] = true; bsfPre[index] = current; return;//直接返回 } if(bfsFlag[index] == false)//如果未访问过 { bfsFlag[index] = true; bsfPre[index] = current; bfsQueue.offer(index); } } } } } private void printBFS(int dstId) { int index = dstId; do { System.out.printf("<-%s", cities.get(index).name); index = bsfPre[index]; }while(index != -1); System.out.println(); } ArrayList<Integer> dfsPath = new ArrayList<Integer>(); boolean[] dfsFlag; private void printDFS() { for(Integer node:dfsPath) { System.out.printf("->%s", cities.get(node).name); } System.out.println(); } public void findPathByDFS(City src,City dst) { System.out.printf("dfs find path between '%s' and '%s'!\n",src.name,dst.name); findPathByDFS(src.id, dst.id); } public void findPathByDFS(int srcId,int dstId) { dfsPath.clear(); dfsFlag = new boolean[A.length]; for(int i=0;i<A.length;i++) { dfsFlag[i] = false; } dfsPath.add(srcId); dfsFlag[srcId] = true; dfs( srcId, dstId); printDFS(); } private void dfs(int srcId,int dstId) { for(int index=0;index<A[srcId].length;index++) { if(srcId == index) continue; if(A[srcId][index]>0)//两者连接 { if(index == dstId)//找到目标了 { dfsFlag[index] = true; dfsPath.add(index); return; } if(dfsFlag[index] == false)//如果该节点未访问过 { dfsFlag[index] = true; dfsPath.add(index); dfs(index,dstId); if(dfsFlag[dstId] == false)//目标没找到 dfsPath.remove(index); else return; } } } } public void createEdge(City a, City b, double w) { A[a.id][b.id]=w; A[b.id][a.id]=w;//added by me! cities.add(a.id,a); cities.add(b.id,b); } public String toString() { String r = "I am a map of " + A.length + " cities."; r += " My connections are:\n"; for (int i=0;i<A.length;i++) { for (int j=0;j<A[0].length;j++) r+=A[i][j]+"\t"; r+="\n"; } return r; } }
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