Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

#include<iostream>
using namespace std;
int p[1001][1001];
int max(int a,int b){
if(a>=b)
return a;
else
return b;
}

int main(){
int a[1000],v[1000];
int t,n,c;
scanf("%d",&t);
while(t--){
scanf("%d%d",&n,&c);
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
for(int i=1;i<=n;i++)
scanf("%d",&v[i]);
memset(p,0,sizeof(p));

for(int i=1;i<=n;i++)
for(int j=0;j<=c;j++){
if(j>=v[i])
p[i][j]=max(p[i-1][j],p[i-1][j-v[i]]+a[i]);
else
p[i][j]=p[i-1][j];
}

/* for(int i=0;i<n;i++)
for(int j=c;j>=v[i];j--){
p[j]=max(p[j],p[j-v[i]]+a[i]);
}
*/
printf("%d\n",p[n][c]);

}

return 0;
}

以上两种方法都可以接受，但注释的方法更高效

解释，可参考http://blog.sina.com.cn/s/blog_7e5541250100rtv5.html

Bone Collector