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HDOJ1159解题报告

题目地址:

  http://acm.hdu.edu.cn/showproblem.php?pid=1159

题目概述:

  给出两个字符串,求最长公共子序列长度。

大致思路:

  很经典的问题,就不多说了。

  附一个我觉得写的很不错的博主的讲解:http://www.cnblogs.com/en-heng/p/3963803.html

代码:

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstdlib>
 4 #include <cmath>
 5 #include <vector>
 6 #include <ctime>
 7 #include <map>
 8 #include <stack>
 9 #include <queue>
10 #include <cstring>
11 #include <algorithm>
12 using namespace std;
13 
14 #define sacnf scanf
15 #define scnaf scanf
16 #define scanfi(x) scanf("%d",&x)
17 #define scanfd(x) scanf("%lf",&x)
18 #define scanfl(x) scanf("%lld",&x)
19 #define scanfc(x) scanf("%c",&x)
20 #define scanfs(x) scanf("%s",x)
21 #define maxn  1010
22 #define maxm 10010
23 #define inf 1061109567
24 #define Eps 0.00001
25 const double PI=acos(-1.0);
26 #define mod 1000000007
27 #define MAXNUM 10000
28 void Swap(int &a,int &b) {int t=a;a=b;b=t;}
29 int Abs(int x) {return (x<0)?-x:x;}
30 typedef long long ll;
31 typedef unsigned int uint;
32 
33 int dp[maxn][maxn];
34 char s1[maxn],s2[maxn];
35 
36 int main()
37 {
38     //freopen("data.in","r",stdin);
39     //freopen("data.out","w",stdout);
40     //clock_t st=clock();
41     while(~scanf("%s%s",s1+1,s2+1))
42     {
43         s1[0]=s;s2[0]=s;
44         int len1=strlen(s1);
45         int len2=strlen(s2);
46         memset(dp,0,sizeof(dp));
47         //if(len1>len2) swap(s1,s2),swap(len1,len2);
48         for(int i=1;i<len1;i++)
49         {
50             for(int j=1;j<len2;j++)
51             {
52                 if(s1[i]==s2[j]) dp[i][j]=dp[i-1][j-1]+1;
53                 else dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
54             }
55         }
56         printf("%d\n",dp[len1-1][len2-1]);
57     }
58     //clock_t ed=clock();
59     //printf("\n\nTime Used : %.5lf Ms.\n",(double)(ed-st)/CLOCKS_PER_SEC);
60     return 0;
61 }

 

HDOJ1159解题报告