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154. Find Minimum in Rotated Sorted Array II

就比1多了一点点

 1     public int findMin(int[] nums) { 2         if(nums.length == 0) { 3             return -1; 4         } 5         int left = 0; 6         int right = nums.length - 1; 7         while(left < right) { 8             int mid = left + (right - left) / 2; 9             if(nums[mid] > nums[right]) {10                 left = mid + 1;11             } else if(nums[mid] < nums[right]) {12                 right = mid;13             } else {14                 right--;15             }16         }17         return nums[left];18     }

第13行,当nums[mid] == nums[high]的时候high--

154. Find Minimum in Rotated Sorted Array II