做法1：

            List<int> list = new List<int>();

            Random rand = new Random();

            while (list.Count < 100)

            {

                int number = rand.Next(1, 101);//>=1,<101

                if (!list.Contains(number))//如果list中已经含有这个数，则不插入

                {

                    list.Add(number);

                }

            }

            foreach (int i in list)

            {

                Console.WriteLine(i);

            }

做法2：

先把1-100这100个数按顺序放入数组arr，再重复100次下面的操作，生成两个介于 >=0,<100 之间的随机数m、n，颠倒arr[m]和arr[n]的数。

            int[] arr = new int[100];

            //把100个数顺序放入

            for (int i = 0; i < 100; i++)

            {

                arr[i] = i + 1;

            }

            Random rand = new Random();

            for (int i = 0; i < 100; i++)

            {

                //随机生成两个位置

                int m = rand.Next(0, 100);

                int n = rand.Next(0, 100);

                //颠倒两个位置

                int temp = arr[m];

                arr[m] = arr[n];

                arr[n] = temp;

            }