寻找图中最小连通的路径，图如下：

算法步骤：

1. Sort all the edges in non-decreasing order of their weight.

2. Pick the smallest edge. Check if it forms a cycle with the spanning tree 
formed so far. If cycle is not formed, include this edge. Else, discard it.  

3. Repeat step#2 until there are (V-1) edges in the spanning tree.

正因为这步，使得原本简单的贪心法，变得不那么简单了。

这样本算法的时间效率达到：max(O(ElogE) , O(ElogV))

原文参考：http://www.geeksforgeeks.org/greedy-algorithms-set-2-kruskals-minimum-spanning-tree-mst/

#pragma once
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

class KruskalsMST
{
	struct Edge
	{
		int src, des, weight;
	};

	static int cmp(const void *a, const void *b)
	{
		Edge *a1 = (Edge *) a, *b1 = (Edge *) b;
		return a1->weight - b1->weight;
	}

	struct Graph
	{
		int V, E;
		Edge *edges;
		Graph(int v, int e) : V(v), E(e)
		{
			edges = new Edge[e];
		}
		virtual ~Graph()
		{
			if (edges) delete [] edges;
		}
	};

	struct SubSet
	{
		int parent, rank;
	};

	int find(SubSet *subs, int i)
	{
		if (subs[i].parent != i)
			subs[i].parent = find(subs, subs[i].parent);
		return subs[i].parent;
	}

	void UnionTwo(SubSet *subs, int x, int y)
	{
		int xroot = find(subs, x);
		int yroot = find(subs, y);
		if (subs[xroot].rank < subs[yroot].rank)
			subs[xroot].parent = yroot;
		else if (subs[xroot].rank > subs[yroot].rank)
			subs[yroot].parent = xroot;
		else
		{
			subs[xroot].rank++;
			subs[yroot].parent = xroot;
		}
	}

	Graph *graph;
	Edge *res;
	SubSet *subs;

	void initSubSet()
	{
		subs = new SubSet[graph->V];
		for (int i = 0; i < graph->V; i++)
		{
			subs[i].parent = i;
			subs[i].rank = 0;
		}
	}

	void mst()
	{
		res = new Edge[graph->V-1];

		qsort(graph->edges, graph->E, sizeof(graph->edges[0]), cmp);

		initSubSet();

		for (int e = 0, i = 0; e < graph->V - 1 && i < graph->E; i++)
		{
			Edge nextEdge = graph->edges[i];
			int x = find(subs, nextEdge.src);
			int y = find(subs, nextEdge.des);
			if (x != y)
			{
				res[e++] = nextEdge;
				UnionTwo(subs, x, y);
			}
		}
	}

	void printResult()
	{
		printf("Following are the edges in the constructed MST\n");
		for (int i = 0; i < graph->V-1; ++i)
			printf("%d -- %d == %d\n", res[i].src, res[i].des, res[i].weight);
	}
public:
	KruskalsMST()
	{
		/* Let us create following weighted graph
		10
		0--------1
		|  \     |
		6|   5\   |15
		|      \ |
		2--------3
		4       */
		int V = 4;  // Number of vertices in graph
		int E = 5;  // Number of edges in graph
		graph = new Graph(V, E);


		// add edge 0-1
		graph->edges[0].src = http://www.mamicode.com/0;>