首页 > 代码库 > 【HDOJ】3789 奥运排序问题
【HDOJ】3789 奥运排序问题
写了个函数指针,这题目很水,但是佷烦。
1 #include <iostream> 2 #include <cstring> 3 #include <cstdio> 4 #include <cstdlib> 5 using namespace std; 6 7 #define MAXN 305 8 9 typedef struct { 10 int id, g, j; 11 float gp, jp; 12 } count_st; 13 14 typedef struct { 15 int r, id; 16 } rank_st; 17 18 count_st counts[MAXN], buf[MAXN]; 19 rank_st rank[4][MAXN]; 20 int ids[MAXN]; 21 int n, m; 22 23 int compg(const void *a, const void *b) { 24 return ((count_st *)b)->g - ((count_st *)a)->g; 25 } 26 27 int compj(const void *a, const void *b) { 28 return ((count_st *)b)->j - ((count_st *)a)->j; 29 } 30 31 int compgp(const void *a, const void *b) { 32 return ((count_st *)b)->gp>((count_st *)a)->gp ? 1:-1; 33 } 34 35 int compjp(const void *a, const void *b) { 36 return ((count_st *)b)->jp>((count_st *)a)->jp ? 1:-1; 37 } 38 39 void f(rank_st *a, int sel, int (*cmp)(const void*, const void *)) { 40 int i, j; 41 qsort(counts, m, sizeof(count_st), cmp); 42 for (i=0, j=0; i<m; ++i) { 43 if (sel == 0) 44 if (i && counts[i].g != counts[i-1].g) 45 j = i; 46 if (sel == 1) 47 if (i && counts[i].j != counts[i-1].j) 48 j = i; 49 if (sel == 2) 50 if (i && counts[i].gp != counts[i-1].gp) 51 j = i; 52 if (sel == 3) 53 if (i && counts[i].jp != counts[i-1].jp) 54 j = i; 55 (a+i)->id = counts[i].id; 56 (a+i)->r = j; 57 } 58 } 59 60 int main() { 61 int i, j, k, v, min; 62 float dp; 63 64 while (scanf("%d %d",&n,&m) != EOF) { 65 for (i=0; i<n; ++i) { 66 buf[i].id = i; 67 scanf("%d %d %f", &buf[i].g, &buf[i].j, &dp); 68 buf[i].gp = buf[i].g / dp; 69 buf[i].jp = buf[i].j / dp; 70 } 71 for (i=0; i<m; ++i) { 72 scanf("%d", &j); 73 counts[i] = buf[j]; 74 ids[i] = j; 75 } 76 f(rank[0], 0, &compg); 77 f(rank[1], 1, &compj); 78 f(rank[2], 2, &compgp); 79 f(rank[3], 3, &compjp); 80 for (i=0; i<m; ++i) { 81 min = MAXN; 82 for (j=0; j<4; ++j) { 83 for (k=0; k<m; ++k) { 84 if (rank[j][k].id == ids[i]) { 85 if (rank[j][k].r < min) { 86 v = j; 87 min = rank[j][k].r; 88 } 89 break; 90 } 91 } 92 } 93 printf("%d:%d\n",min+1,v+1); 94 } 95 printf("\n"); 96 } 97 98 return 0; 99 }
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