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LeetCode58 Length of Last Word

题目:

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5. (Easy)

分析:

注意把最后的空格处理掉即可。

代码:

 1 class Solution { 2 public: 3     int lengthOfLastWord(string s) { 4         int start = s.size() - 1; 5         int result = 0; 6         while (s[start] ==  ) { 7             start--; 8         } 9         for (int i = start; i >= 0; --i) {10             if (s[i] !=  ) {11                 result++;12             }13             else {14                 return result;15             }16         }17         return result;18     }19 };

 

LeetCode58 Length of Last Word