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58. Length of Last Word
1. 问题描述
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World",return 5.
Tags: String
2. 解题思路
字符串操作
3. 代码
class Solution {public: int lengthOfLastWord(string s) { string::size_type pos = s.find_last_not_of(‘ ‘); if (pos != s.npos) { string sTemp = s.substr(0, pos+1); pos = sTemp.rfind(‘ ‘); if (pos != sTemp.npos) { return sTemp.length() - pos - 1; } else { return sTemp.length(); } } return 0; }};
4. 反思
58. Length of Last Word
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