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CDZSC_2015寒假新人（4）——搜索 N

2024-11-19 11:18:02   203人阅读

Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u

Description

Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward. In this problem, you are asked to implement this. 
The following commands need to be supported: 
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored. 
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored. 
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied. 
QUIT: Quit the browser. 
Assume that the browser initially loads the web page at the URL http://www.acm.org/

Input

Input is a sequence of commands. The command keywords BACK, FORWARD, VISIT, and QUIT are all in uppercase. URLs have no whitespace and have at most 70 characters. You may assume that no problem instance requires more than 100 elements in each stack at any time. The end of input is indicated by the QUIT command.

Output

For each command other than QUIT, print the URL of the current page after the command is executed if the command is not ignored. Otherwise, print "Ignored". The output for each command should be printed on its own line. No output is produced for the QUIT command.

Sample Input

VISIT http://acm.ashland.edu/VISIT http://acm.baylor.edu/acmicpc/BACKBACKBACKFORWARDVISIT http://www.ibm.com/BACKBACKFORWARDFORWARDFORWARDQUIT

Sample Output

http://acm.ashland.edu/http://acm.baylor.edu/acmicpc/http://acm.ashland.edu/http://www.acm.org/Ignoredhttp://acm.ashland.edu/http://www.ibm.com/http://acm.ashland.edu/http://www.acm.org/http://acm.ashland.edu/http://www.ibm.com/Ignored




思路：这题模拟栈。自己开一个数组和栈头指针和栈尾指针来模拟。。。。。坑点：因为浏览器的特点当你在前进后退的途中输入一个网站，那么他那么这个网站的位置到栈尾的网站全部清空了，也就是说栈尾就是你输入的这个网站。



#include <iostream>#include <cstdio>#include <cstring>using namespace std;char str[100][130];int main(){#ifdef CDZSC_OFFLINE    freopen("in.txt","r",stdin);#endif    char str1[10],a[100];    int n,m;    n=0,m=0;    memset(str,0,sizeof(str));    strcpy(str[0],"http://www.acm.org/");    while(scanf("%s",str1)!=EOF)    {        if(strcmp(str1,"VISIT")==0)        {            scanf("%s",a);            strcpy(str[++n],a);            m=n;//后面的网站会被清空            printf("%s\n",str[m]);        }        else if(strcmp(str1,"BACK")==0)        {            n--;            if(n<0)            {                n=0;                printf("Ignored\n");            }            else            {                printf("%s\n",str[n]);            }        }        else if(strcmp(str1,"FORWARD")==0)        {            n++;            if(n>m)            {                n=m;                printf("Ignored\n");            }            else            {                printf("%s\n",str[n]);            }        }        else if(strcmp(str1,"QUIT")==0)        {            break;        }    }    return 0;}

 

CDZSC_2015寒假新人（4）——搜索 N


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