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2017"百度之星"程序设计大赛 - 初赛(A)

2017"百度之星"程序设计大赛 - 初赛(A)

hdu6108    求出 n-1 的因子个数即可

#include<bits/stdc++.h>using namespace std;#pragma comment(linker, "/STACK:102400000,102400000")#define rep(i,a,b) for (int i=a; i<=b; ++i)#define per(i,b,a) for (int i=b; i>=a; --i)#define mes(a,b)  memset(a,b,sizeof(a))#define INF 0x3f3f3f3f#define MP make_pair#define PB push_back#define fi  first#define se  secondtypedef long long ll;const int N = 200005;int main(){    int T;  scanf("%d", &T);    int n;    while(T--)    {        scanf("%d", &n);        int ans=0;        for(int i=1; i<(int)sqrt(n-1); ++i)            if((n-1)%i==0) ans += 2;        if((n-1)%(int)sqrt(n-1)==0) ++ans;        printf("%d\n", ans);    }    return 0;}

 

hdu6112     暴力模拟

#include<bits/stdc++.h>using namespace std;#pragma comment(linker, "/STACK:102400000,102400000")#define rep(i,a,b) for (int i=a; i<=b; ++i)#define per(i,b,a) for (int i=b; i>=a; --i)#define mes(a,b)  memset(a,b,sizeof(a))#define INF 0x3f3f3f3f#define MP make_pair#define PB push_back#define fi  first#define se  secondtypedef long long ll;const int N = 200005;int num[15][35];int m[15]={0,31,28,31,30,31,30,31,31,30,31,30,31};void getnum(){    int sum=0;    rep(i,1,12) rep(j,1,m[i])    {        ++sum,  num[i][j]=sum;    }    num[2][29]=num[2][28];}int is(int year){    return ( year%400==0 || (year%4==0 && year%100!=0) );}int isday(int year, int mon, int day){    return num[mon][day] + (is(year) && (mon>2 || (mon==2 && day==29)));}int main(){    getnum();      int T;  scanf("%d", &T);    while(T--)    {        int year, mon, day;        scanf("%d-%d-%d", &year, &mon, &day);        ll  cnt=0, cnt1;        rep(i,2001,year-1) cnt += 365+is(i);        cnt1 = cnt;        cnt += isday(year,mon,day);        int dat = cnt%7,  ans;          rep(i,year,10000)        {            cnt1 += 365+is(i);            if(!(mon==2 && day==29) || is(i+1))            {                cnt1 += isday(i+1,mon,day);                if(cnt1%7==dat) { ans=i+1; break; }                cnt1 -= isday(i+1,mon,day);            }        }        printf("%d\n", ans);    }    return 0;}

 

hdu6113   并查集,找出连通快判断即可

#include<bits/stdc++.h>using namespace std;#pragma comment(linker, "/STACK:102400000,102400000")#define rep(i,a,b) for (int i=a; i<=b; ++i)#define per(i,b,a) for (int i=b; i>=a; --i)#define mes(a,b)  memset(a,b,sizeof(a))#define INF 0x3f3f3f3f#define MP make_pair#define PB push_back#define fi  first#define se  secondtypedef long long ll;const int N = 110;int id[N][N], fa[N*N], n, m, num0[N*N];char s[N][N];bool is(int x, int y){    return x>0 && y>0 && x<=n && y<=m;}int Find(int x) {    return fa[x]==x ? x : fa[x]=Find(fa[x]);}void Unite(int a, int b){    int faa=Find(a), fab=Find(b);    if(faa!=fab) fa[faa]=fa[fab];}int main(){    while(~scanf("%d%d", &n, &m))    {        int tot=0;        rep(i,1,n)        {            scanf("%s", s[i]+1);            rep(j,1,m) id[i][j]=++tot;        }        rep(i,1,tot) fa[i] = i;        rep(i,1,n) rep(j,1,m)        {            if(is(i-1,j) && s[i-1][j]==s[i][j]) Unite(id[i-1][j], id[i][j]);            if(is(i+1,j) && s[i+1][j]==s[i][j]) Unite(id[i+1][j], id[i][j]);            if(is(i,j+1) && s[i][j+1]==s[i][j]) Unite(id[i][j+1], id[i][j]);            if(is(i,j-1) && s[i][j-1]==s[i][j]) Unite(id[i][j-1], id[i][j]);        }        int  cnt=0;   mes(num0, 0);        int cnt1=0;        rep(i,1,n) rep(j,1,m)        {            if(s[i][j]==1 && fa[id[i][j]]==id[i][j]) ++cnt;            if(s[i][j]==0 && fa[id[i][j]]==id[i][j]) ++num0[fa[id[i][j]]], ++cnt1;        }        if(cnt!=1) { puts("-1"); continue; }        cnt=0;        rep(ca,1,tot) if(num0[ca])        {            bool  flag=0;            rep(i,1,n) {                rep(j,1,m) if(s[i][j]==0 && fa[id[i][j]]==ca) {                    if(i==1 || i==n || j==1 || j==m) { flag=1;  break; }                }                if(flag) break;            }            if(flag==0) ++cnt;        }        if(cnt==1) puts("0");        else if(cnt==0) puts("1");        else puts("-1");    }    return 0;}

2017"百度之星"程序设计大赛 - 初赛(A)