题目描写叙述：

Given a binary tree, return the postorder traversal of its nodes‘ values.

For example:
Given binary tree {1,#,2,3},

   1
         2
    /
   3

return [3,2,1].

代码：

vector<int> Solution::postorderTraversal(TreeNode *root)
{
    vector<int> postorderSequence;
    stack<TreeNode*> treeNodeStack;
    TreeNode * node = root;
    if(node == NULL)
        return postorderSequence;
    postorderSequence.push_back(node->val);
    if(node->left)
        treeNodeStack.push(node->left);
    if(node->right)
        treeNodeStack.push(node->right);
    while(!treeNodeStack.empty())
    {
        node = treeNodeStack.top();
        treeNodeStack.pop();
        postorderSequence.push_back(node->val);
        if(node->left)
            treeNodeStack.push(node->left);
        if(node->right)
            treeNodeStack.push(node->right);
    }
    reverse(postorderSequence.begin(),postorderSequence.end());
    return postorderSequence;
}