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235. Lowest Common Ancestor of a Binary Search Tree 二叉搜索树的LCA
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______ / ___2__ ___8__ / \ / 0 _4 7 9 / 3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
二叉搜索树,公共祖先的值一定大于等于较小的节点,小于等于较大的节点。换言之,在遍历树的时候,如果当前结点大于两个节点,则结果在当前结点的左子树里,如果当前结点小于两个节点,则结果在当前节点的右子树里。
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public TreeNode LowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if(root.val > p.val && root.val > q.val) return LowestCommonAncestor(root.left, p, q);
if(root.val < p.val && root.val < q.val) return LowestCommonAncestor(root.right, p, q);
return root;
}
}
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235. Lowest Common Ancestor of a Binary Search Tree 二叉搜索树的LCA
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