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HihoCoder - 1498 Diligent Robots

There are N jobs to be finished. It takes a robot 1 hour to finish one job.

At the beginning you have only one robot. Luckily a robot may build more robots identical to itself. It takes a robot Q hours to build another robot.  

So what is the minimum number of hours to finish N jobs?

Note two or more robots working on the same job or building the same robot won‘t accelerate the progress.

Input

The first line contains 2 integers, N and Q.  

For 70% of the data, 1 <= N <= 1000000  

For 100% of the data, 1 <= N <= 1000000000000, 1 <= Q <= 1000

Output

The minimum number of hours.

Sample Input

10 1

Sample Output

5

解题思路:
被签到题卡了半天也是日了狗了,直接暴力就能过结果非要去推公式求导,结果还求错了。。。
#include<iostream>#include<cmath>using namespace std;#define ll long longint main(){    ll m,q,ans=0,i,t;    cin>>m>>q;    ll sum = 999999999;    while(1){        if(pow(2,ans)>m)            break;        t=ans*q+m/(pow(2,ans));        int num = m/pow(2,ans);        if(m-pow(2,ans)*num!=0)            t++;        sum = min(t,sum);        ans++;    }    cout<<sum<<endl;}

 

HihoCoder - 1498 Diligent Robots