代码：

 class Solution { 

public: 

    /**

     * @param grid: a list of lists of integers.

     * @return: An integer, minimizes the sum of all numbers along its path

     */ 

    int min(int a, int b){ 

        if (a < b) return a; 

        else return b; 

    } 

    int minPathSum(vector<vector<int> > &grid) { 

        // write your code here 

        int m = grid.size(); 

        int n = grid[0].size(); 

        int dp[m][n]; 

        dp[0][0] = grid[0][0]; 

        for (int i = 1; i < m; i++) 

            dp[i][0] = dp[i-1][0] + grid[i][0]; 

        for (int j = 1; j < n; j++) 

            dp[0][j] = dp[0][j-1] + grid[0][j]; 

        for (int i = 1; i < m; i++) 

            for (int j = 1; j < n; j++) 

                dp[i][j] = min(dp[i-1][j], dp[i][j-1]) + grid[i][j]; 

        return dp[m-1][n-1]; 

    }  

lintcode截图：

二叉树的最大深度