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七夕专场-A题

这个题目意思我给弄错了。真桑心没好好听TK的指导,只要在松弛操作里头记录前驱节点就可以了,还要注意long long,其实我有很多时候测试错了可以猜到要用long long才可以,但是不知道缘故,就单单怎么算,不是很了解。

#include <cstdio>#include <iostream>#include <cstring>#include <queue>#include <algorithm>#include <algorithm>#define LL long longusing namespace std;const int maxn = 200010;const int maxm = 200100;typedef pair<LL,int> pii;int v[maxm],next[maxm],w[maxm];int first[maxn];LL d[maxn];int e;int temp[maxn];int re[maxn];void init(){    e = 0;    memset(first,-1,sizeof(first));}void add_edge(int a,int b,int c){    v[e] = b;next[e] = first[a];w[e] = c;first[a] = e++;}void dij(int src){    priority_queue <pii,vector<pii>,greater<pii> > q;    memset(d,-1,sizeof(d));    d[src] = 0;    q.push(make_pair(0,src));    while(!q.empty()){        int u = q.top().second;        q.pop();        for(int i = first[u];i != -1;i = next[i]){            if(d[v[i]] == -1 || d[v[i]] > d[u]+w[i]){                temp[v[i]] = u;                d[v[i]] = d[u]+w[i];                q.push(make_pair(d[v[i]],v[i]));            }        }    }}int main(){      int m,n;cin >> m >> n;      int a ,b,c;        init();        for(int i = 0;i < n;i++){         cin >> a >> b >> c;            add_edge(a,b,c);            add_edge(b,a,c);        }        dij(1);        int p = 0,now = m;        if(d[m] == -1)        {            cout << "-1" << endl;            return 0;        }        re[p++] = m;        while(now != 1)        {            now = temp[now];            re[p++] = now;        }        for(int i = p-1;i >0;i--)        {            cout << re[i] << " ";        }        cout << re[0] << endl;    return 0;}