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POJ 1466 Girls and Boys 求最大独立点集

最大独立点集 = 点数 - 最大匹配数

注意这题因为是两两匹配,A匹配B B匹配A算两个,所以最大匹配数要除以2

 

#include <cstdio>#include <cstring>#include <cmath>#include <algorithm>#include <climits>#include <string>#include <iostream>#include <map>#include <cstdlib>#include <list>#include <set>#include <queue>#include <stack>using namespace std;typedef long long LL;const int maxn = 505;bool g[maxn][maxn];bool vis[maxn];int n,bx[maxn],by[maxn];int dfs(int now) {    for(int i = 0;i < n;i++) if(g[now][i] && !vis[i]) {        vis[i] = true;        if(!by[i] || dfs(by[i])) {            by[i] = now; bx[now] = i;            return 1;        }    }    return 0;}void solve() {    memset(bx,0,sizeof(bx));    memset(by,0,sizeof(by));    int ans = 0;    for(int i = 0;i < n;i++) if(!bx[i]) {        memset(vis,0,sizeof(vis));        if(dfs(i)) ans++;    }    printf("%d\n",n - ans / 2);}int main() {    while(scanf("%d",&n) != EOF) {        memset(g,0,sizeof(g));        for(int i = 0;i < n;i++) {            int cnt,id; scanf("%d: (%d)",&id,&cnt);            for(int j = 0;j < cnt;j++) {                int tmp; scanf("%d",&tmp);                g[id][tmp] = true;            }        }        solve();    }    return 0;}