找出循环周期就行了

#include<bits/stdc++.h>
using namespace std;
int N,M,X;
int time(int x,int y,int z)
{
    if(z!=0&&x==1)
        return z;
    if(x%2==0)
        x/=2;
    else
        x=(x+y+1)/2;
    return time(x,y,z+1);
}
int operate(int x)
{
    if(x<=N/2)
        return x*2;
    else
        return (x-N/2)*2-1;
}
int main()
{
    while(scanf("%d%d%d",&N,&M,&X)==3)
    {
        M%=time(1,N,0);
        for(int i=1;i<=X;i++)
        {
            if(i!=1)
                printf(" ");
            int ans=i;
            for(int j=1;j<=M;j++)
                ans=operate(ans);
            printf("%d",ans);
        }
        printf("\n");
    }
    return 0;
}