题意：给定背包体积与物品的体积与价值 求正好放完的最小价值
#include<iostream>
using namespace std;
int min(int a,int b)
{
    if(a<b) return a;
    return b;
}
int main()
{
    int t,m1,m2,n,i,j;
    int v[502],w[502],dp[10005],m;
    cin>>t;
    while(t--)
    {
        cin>>m1>>m2;
        m=m2-m1;
        cin>>n;
        for(i=1;i<=n;i++)
            cin>>v[i]>>w[i];
        for(i=1;i<=m;i++)
            dp[i]=-2000000000;
        dp[0]=0;
        for(i=1;i<=n;i++)
            for(j=w[i];j<=m;j++)
                if(dp[j]<0) dp[j]=dp[j-w[i]]+v[i];//j个容量能装下的最小值是 能装下w[i]重量的值+j-w[i]能装下的最小值
                else if(dp[j-w[i]]+v[i]>0)
                    dp[j]=min(dp[j],dp[j-w[i]]+v[i]);//j-w[i]是上一为状态
        if(dp[m]>0)
            cout<<"The minimum amount of money in the piggy-bank is "<<dp[m]<<"."<<endl;
        else
            cout<<"This is impossible."<<endl;
    }
    return 0;
}