HighwaysTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 22433 Accepted: 10341DescriptionThe island nation of Flatopia is perfectly
https://www.u72.net/daima/1h5u.html - 2024-07-18 19:51:35 - 代码库Problem Description The Head Elder of the tropical island of Lagrishan has a problem. A burst of foreign aid money was spent on extra roads
https://www.u72.net/daima/1zkr.html - 2024-08-30 01:25:55 - 代码库Problem Description某省调查城镇交通状况,得到现有城镇道路统计表,表中列出了每条道路直接连通的城镇。省政府“畅通工程”的目标是使全省任何两个城镇
https://www.u72.net/daima/1zdf.html - 2024-08-30 01:28:55 - 代码库Problem Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can
https://www.u72.net/daima/1n94.html - 2024-08-30 01:04:16 - 代码库1 /* 2 题意:N个城市中每两个城市有多条路径连接,可是因为路径存在的天数是有限的!以为某条路经不存在了 3 导致N个城市不能连通了,那么村名们就
https://www.u72.net/daima/xsns.html - 2024-07-17 02:18:09 - 代码库题意:给定完全无向图,求其中m个子节点,要求Sum(edge)/Sum(node)最小。思路:由于N很小,枚举所有可能的子节点可能情况,然后求MST,memset()在POJ里面需要memory
https://www.u72.net/daima/0x7h.html - 2024-07-18 05:48:59 - 代码库今天是个阴天,下了点雨,work .........步骤:将所有边排序,然后不断从小到大加上边,这个过程最重要的是避免环的产生,此处用并查集。(nyoj 38) 1 package 最
https://www.u72.net/daima/3n2b.html - 2024-07-20 20:23:37 - 代码库题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=3371 题目不难 稍微注意一下 要把已经建好的城市之间的花费定义为0,在用普通Prim算法就可以了;我没
https://www.u72.net/daima/2h7s.html - 2024-07-19 21:19:43 - 代码库Jungle RoadsTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 19265 Accepted: 8806DescriptionThe Head Elder of the tropical island
https://www.u72.net/daima/xxdh.html - 2024-07-17 05:44:27 - 代码库题意:。。。难点:如何判断是不是信息不全:在输入的时候建立并查集,之后判断有几个节点就可以了,剩下的就是kruskal算法。代码:#include<stdio.h>#include<st
https://www.u72.net/daima/xxws.html - 2024-07-17 05:59:14 - 代码库畅通工程Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 17594 Accepted Submissio
https://www.u72.net/daima/17me.html - 2024-07-19 13:46:38 - 代码库畅通工程Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27972 Accepted Submis
https://www.u72.net/daima/73sk.html - 2024-09-10 12:18:43 - 代码库Slim SpanTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 7933 Accepted: 4227DescriptionGiven an undirected weig
https://www.u72.net/daima/5w36.html - 2024-09-06 19:16:37 - 代码库题目链接:http://poj.org/problem?id=3026题意:题意就是从起点开始可以分成多组总权值就是各组经过的路程,每次到达一个&lsquo;A‘点可以继续分组,但是在路
https://www.u72.net/daima/7mf0.html - 2024-09-11 00:18:59 - 代码库The Head Elder of the tropical island of Lagrishan has a problem. A burst of foreign aid money was spent on extra roads between villages som
https://www.u72.net/daima/7nnh.html - 2024-09-09 10:04:21 - 代码库http://lx.lanqiao.cn/problem.page?gpid=T16题意:n个点,p条边,n,p<=1e5.每个点都有权值c[i],求选择一个点出发遍历所有点后返回需要的最小代价?容易
https://www.u72.net/daima/68e0.html - 2024-09-09 04:01:05 - 代码库题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4786题意:给定图的n个点和m条双向边,告诉你每条边的权值。权值为1表示该边是白边,权值为0表示该边
https://www.u72.net/daima/m5wm.html - 2024-09-17 12:50:20 - 代码库题意 输入n 然后输入n个数 代表连接时每个站点自身的消耗 然后输入n*n的矩阵 第i行第j列的数代表第i个站点和第j个站点之间路上的花费 链接i,j
https://www.u72.net/daima/ee8n.html - 2024-07-29 01:55:12 - 代码库问题描述Farmer John变得非常懒,他不想再继续维护供奶牛之间供通行的道路。道路被用来连接N个牧场,牧场被连续地编号为1到N。每一个牧场都是一个奶牛的家
https://www.u72.net/daima/81wv.html - 2024-09-12 02:36:17 - 代码库解题关键:注意下标解法一:prim算法 1 #include<bits/stdc++.h> 2 #define maxv 1002 3 #define maxm 50002 4 #define INF 0x3f3f3f3f 5 using namespace
https://www.u72.net/daima/nku98.html - 2024-09-26 17:07:39 - 代码库