注意输出就没了。。。 1 #include<cstdio> 2 #include<cstring> 3 using namespace std; 4 int gcd(int a, int b) 5 { 6 return b==0?a:gc
https://www.u72.net/daima/83h7.html - 2024-09-12 05:06:56 - 代码库//3中天气前一天天气为i转为第二天天气为j的概率为p[i][j]//问第一天天气为i,n天后天气为j的概率//dp[i][j][k]在第一天天气为j的情况下第n天的天
https://www.u72.net/daima/mch5.html - 2024-09-16 17:45:35 - 代码库首先要解决的是输入输出的问题。作为一个渣渣新手,我用以前学的 C++写了错误代码提交,后果可想而知。所以认认真真的看了【ACM新手之八大输入输出】,格式
https://www.u72.net/daima/87x5.html - 2024-07-26 20:40:25 - 代码库题意:有n个队参加CCPC,然后有两种优惠方式,一种是一天买再次,一种是买两天,现在让你判断能不能找到一种方式,使得优惠不剩余。析:直接模拟,如果本次是奇数,那么
https://www.u72.net/daima/f0hc.html - 2024-08-16 23:55:30 - 代码库2456: modeTime Limit: 1 Sec Memory Limit: 1 MB Submit: 4868 Solved: 2039 [Submit][Status][Discuss]Description给你一个n个数的数列,其中某个数
https://www.u72.net/daima/nksad.html - 2024-09-26 11:03:02 - 代码库题意:给n个用户名和密码,把密码中的1改为@,0改为%,l改为L,O改为o。让你输出需要修改密码的用户名个数,以及对应的用户名和密码,按输入的顺序。如果没有用户
https://www.u72.net/daima/nabbm.html - 2024-09-18 08:35:23 - 代码库//从0到n有n+1个格子//对于格子i,掷一次骰子的数为x。那么能够从位置i到位置i+x//格子之间有连线,假设格子a和b有连线,那么从a到b不用掷骰子//求
https://www.u72.net/daima/nadmz.html - 2024-09-18 08:08:15 - 代码库The SnailTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1488 Accepted Submissi
https://www.u72.net/daima/nh5f7.html - 2024-08-03 07:13:14 - 代码库貌&#20284;是当年楼教主出的题目。有N个旅店,两个属性,距离D,价&#26684;C。选择旅店,若选择M1.比M近的,价&#26684;比它高2.比M便宜的,距离比它远求有多少个这
https://www.u72.net/daima/nhk40.html - 2024-08-02 13:10:12 - 代码库但凡从事互联网的人基本都会写几行html,用过Word的人用Dreamweaver也能做出规整的页面,所以大部分人会很自然地认为“页面 的开发没什么技术含量,很简单”
https://www.u72.net/daima/nds3b.html - 2024-09-30 01:00:39 - 代码库http://poj.org/problem?id=2051ArgusTime Limit: 1000MS Memory Limit: 30000KTotal Submissions: 9716 Accepted: 4543DescriptionA data stream is
https://www.u72.net/daima/nnu3b.html - 2024-07-31 17:39:06 - 代码库kmp的讲解:http://blog.csdn.net/u013076044/article/details/41833325 next数组的详细讲解:http://blog.csdn.net/yearn520/article/details/6729
https://www.u72.net/daima/nsshw.html - 2024-08-10 08:52:58 - 代码库Treasure the new start, freshmen!Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1
https://www.u72.net/daima/nv0ae.html - 2024-10-31 08:26:01 - 代码库You Are All ExcellentTime Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3191 Accep
https://www.u72.net/daima/nr4nk.html - 2024-08-09 15:26:02 - 代码库Sempr == The Best Problem Solver?Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 1
https://www.u72.net/daima/nsma9.html - 2024-10-20 10:52:38 - 代码库UVA11636-Hello World!Time limit: 1.000 secondsWhen you ?rst made the computer to print the sentence “Hello World!”, you felt so
https://www.u72.net/daima/nvhbb.html - 2024-10-28 08:38:01 - 代码库Description贝茜在珠宝店闲逛时,买到了一个中意的手镯。很自然地,她想从她收集的 N(1 <= N <= 3,402)块宝石中选出最好的那些镶在手镯上。对于第i块宝石,
https://www.u72.net/daima/nam0d.html - 2024-07-31 06:04:00 - 代码库Description清早6:00,Farmer John就离开了他的屋子,开始了他的例行工作:为贝茜挤奶。前一天晚上,整个农场刚经受过一场瓢泼大雨的洗礼,于是不难想见,FJ 现在面
https://www.u72.net/daima/nam3h.html - 2024-07-31 06:10:00 - 代码库Binary NumbersTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2828 Accepted Sub
https://www.u72.net/daima/ndn49.html - 2024-08-04 16:47:13 - 代码库题意:找出这些串中最长的公共子串(长度&ge;3),如果长度相同输出字典序最小的那个。分析:用库函数strstr直接查找就好了,用KMP反而是杀鸡用牛刀。 1 #includ
https://www.u72.net/daima/nkm7h.html - 2024-08-04 15:02:20 - 代码库