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poj3349--Snowflake Snow Snowflakes（hash）
| Time Limit: 4000MS | Memory Limit: 65536K | |
| Total Submissions: 31423 | Accepted: 8297 |
Description
You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.
Input
The first line of input will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed byn lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5.
Output
If all of the snowflakes are distinct, your program should print the message:
No two snowflakes are alike.
If there is a pair of possibly identical snow akes, your program should print the message:
Twin snowflakes found.
Sample Input
21 2 3 4 5 64 3 2 1 6 5
Sample Output
Twin snowflakes found.
纠结了好长时间的一个题目，hash过，对100000内的最大素数取余，得到的结果用vec存一下，在对每一个比较12次 得出结果
#include <cstdio>#include <cstring>#include <algorithm>#include <vector>using namespace std;#define maxn 99991struct node{ int a[6] ;} p[200000];vector <int> vec[100000];vector <int>::iterator it ;int cnt , a[6] ;void add(){ int i , sum = 0 ; for(i = 0 ; i < 6 ; i++) { p[cnt].a[i] = a[i] ; sum += a[i] ; } sum %= maxn ; vec[sum].push_back(cnt); cnt++ ;}int find1(int k){ int i , j , l ; for(it = vec[k].begin(); it != vec[k].end() ; it++) { for(i = 0 ; i < 6 ; i++) { for(j = 0 ; j < 6 ; j++) { l = i+j ; if(l >= 6) l -= 6 ; if( p[ *it ].a[j] != a[l] ) break; } if( j == 6 ) return 1 ; } for(i = 0 ; i < 6 ; i++) { for(j = 0 ; j < 6 ; j++) { l = i-j ; if(l < 0) l += 6 ; if( p[ *it ].a[j] != a[l] ) break; } if(j == 6) return 1 ; } } return 0 ;}int main(){ int i , j , n , sum , flag = 0 ; cnt = 0 ; scanf("%d", &n); while(n--) { sum = 0 ; for(i = 0 ; i < 6 ; i++) { scanf("%d", &a[i]); sum += a[i] ; } if(flag) continue ; sum %= maxn ; flag = find1(sum); add(); } if(flag) printf("Twin snowflakes found.\n"); else printf("No two snowflakes are alike.\n"); return 0;}
poj3349--Snowflake Snow Snowflakes（hash）