首页 > 代码库 > UVaLive 6680 Join the Conversation (DP)

UVaLive 6680 Join the Conversation (DP)

题意:给出n条发言,让你求最大的交流长度并输出标记顺序。

析:这个题要知道的是,前面的人是不能at后面的人,只能由后面的人at前面的,那就简单了,我们只要更新每一层的最大值就好,并不会影响到其他层。

最后再从这 n 层中取出最大值,在更新时,也可以记录着最大值。

代码如下:

#pragma comment(linker, "/STACK:1024000000,1024000000")#include <cstdio>#include <string>#include <cstdlib>#include <cmath>#include <iostream>#include <cstring>#include <set>#include <queue>#include <algorithm>#include <vector>#include <map>#include <cctype>#include <cmath>#include <sstream>#include <stack>//#include <tr1/unordered_map>#define freopenr freopen("in.txt", "r", stdin)#define freopenw freopen("out.txt", "w", stdout)using namespace std;//using namespace std :: tr1;typedef long long LL;typedef pair<int, int> P;const int INF = 0x3f3f3f3f;const double inf = 0x3f3f3f3f3f3f;const LL LNF = 0x3f3f3f3f3f3f;const double PI = acos(-1.0);const double eps = 1e-8;const int maxn = 5e4 + 5;const int mod = 1e9 + 7;const int N = 1e6 + 5;const int dr[] = {-1, 0, 1, 0, 1, 1, -1, -1};const int dc[] = {0, 1, 0, -1, 1, -1, 1, -1};const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};inline LL gcd(LL a, LL b){  return b == 0 ? a : gcd(b, a%b); }int n, m;const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};inline int Min(int a, int b){ return a < b ? a : b; }inline int Max(int a, int b){ return a > b ? a : b; }inline LL Min(LL a, LL b){ return a < b ? a : b; }inline LL Max(LL a, LL b){ return a > b ? a : b; }inline bool is_in(int r, int c){    return r >= 0 && r < n && c >= 0 && c < m;}map<string, P> mp;int dp[maxn], pre[maxn];void print(int pos){    if(!pre[pos]){  printf("%d", pos); return; }    print(pre[pos]);    printf(" %d", pos);}int main(){    while(scanf("%d", &n) == 1){        string line, s;        getchar();        mp.clear();        for(int i = 1; i <= n; ++i){            getline(cin, line);            stringstream ss(line);            ss >> s;            string str = s.substr(0, s.size()-1);            dp[i] = 1, pre[i] = 0;            while(ss >> s){                if(!mp.count(s) || s == str)  continue;                if(mp[s].first + 1 > dp[i]){                    dp[i] = mp[s].first + 1;                    pre[i] = mp[s].second;                }            }            if(mp[str].first < dp[i])  mp[str] = P(dp[i], i);        }        int ans = 0, pos;        for(int i = 1; i <= n; ++i)            if(dp[i] > ans) ans = dp[i], pos = i;        printf("%d\n", ans);        print(pos);        printf("\n");    }    return 0;}

 

UVaLive 6680 Join the Conversation (DP)