首页 > 代码库 > Trie树 POJ1056 IMMEDIATE DECODABILITY

Trie树 POJ1056 IMMEDIATE DECODABILITY

2024-07-06 12:25:17   226人阅读

题目：http://poj.org/problem?id=1056

题意：判断是否有串是其他串的前缀

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
#include<algorithm>
#include<stdio.h>
#include<iostream>
#include<set>
#include<map>
#include<queue>
#include<stack>
#include<string.h>
 
using namespace std;
 
struct Node
{
    int cnt;Node * next[50];
}e[111111];
 
int len=0;
 
Node * newnode()
{
    memset(&e[len],0,sizeof(e[len]));
    return &e[len++];
}
 
void Insert(char *s,Node *root)
{
    int len=strlen(s);
    for(int i=0;i<len;i++){
        int cc=s[i]-‘0‘;
        if(!root->next[cc]){
            root->next[cc]=newnode();
        }
        root->cnt++;
        root=root->next[cc];
    }
    root->cnt++;
}
 
int Find(char *s,Node *root)
{
    int len=strlen(s);
    for(int i=0;i<len;i++){
        int cc=s[i]-‘0‘;
        root=root->next[cc];
    }
    if(root->cnt>1)
    return 1;
    else
        return 0;
}
char str[1005][1005];
int main()
{
    int i=-1;int ret=1;int flag=0;Node *root=newnode();
    while(scanf("%s",&str[++i])!=EOF){
        Insert(str[i],root);
        if(strcmp(str[i],"9")==0){
            for(int j=0;j<i;j++){
                if(Find(str[j],root)){
                    flag=1;
                    printf("Set %d is not immediately decodable\n",ret++);break;
                }
            }
            if(flag==0){
                printf("Set %d is immediately decodable\n",ret++);
            }
            i=-1;len=0;flag=0;root=newnode();
        }
    }
    return 0;
}

　　


联系
我们