Implement regular expression matching with support for ‘.‘ and ‘*‘.

‘.‘ Matches any single character.‘*‘ Matches zero or more of the preceding element.The matching should cover the entire input string (not partial).The function prototype should be:bool isMatch(const char *s, const char *p)Some examples:isMatch("aa","a") → falseisMatch("aa","aa") → trueisMatch("aaa","aa") → falseisMatch("aa", "a*") → trueisMatch("aa", ".*") → trueisMatch("ab", ".*") → trueisMatch("aab", "c*a*b") → true

class Solution {public:    bool isMatch(const char *s, const char *p) {        for( char c = *p; c != 0; ++s, c = *p ) {            if( *(p+1) != ‘*‘ )                p++;            else if( isMatch( s, p+2 ) )                return true;            if( (*s==0) || ((c!=‘.‘) && (c!=*s)) )                return false;        }        return *s == 0;    }};

Regular Expression Matching