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Linked List Cycle II
Given a linked list, return the node where the cycle begins. If there is no cycle, return null
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Follow up:
Can you solve it without using extra space?
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; * 2*x+ind - x = c * x+ind = c * x = count - ind */class Solution {public: ListNode *detectCycle(ListNode *head) { ListNode *slow, *fast; slow = fast = head; int count = 0; while(true){ if(slow==NULL || fast==NULL || slow->next==NULL || fast->next==NULL){ return NULL; } slow = slow->next; fast = fast->next->next; count++; if(slow == fast){ //has a cycle while(true){ if(head == slow){ return slow; } head = head->next; slow = slow->next; } } } }};
Linked List Cycle II
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