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Linked List Cycle II
Given a linked list, return the node where the cycle begins. If there is no cycle, return null
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Follow up:
Can you solve it without using extra space?
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution {10 public:11 ListNode *detectCycle(ListNode *head) {12 13 ListNode *fast = head;14 ListNode *slow = head;15 16 if(fast == NULL || fast == NULL)17 return NULL;18 19 while(fast->next != NULL && fast->next->next != NULL)20 {21 fast = fast->next->next;22 slow = slow->next;23 if(fast == slow)24 {25 slow = head;26 while(fast != slow)27 {28 fast = fast->next;29 slow = slow->next;30 }31 return fast;32 }33 }34 return NULL;35 }36 };
Linked List Cycle II
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