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Combination Sum II
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5 and target 8,
A solution set is: [1, 7] [1, 2, 5] [2, 6] [1, 1, 6]
C++实现代码：
#include<iostream>#include<vector>#include<algorithm>using namespace std;class Solution {public: vector<vector<int> > combinationSum2(vector<int> &num, int target){ if(num.empty()) return vector<vector<int> >(); sort(num.begin(),num.end()); vector<vector<int> > ret; vector<int> path; combination(num,0,target,ret,path); return ret; } void combination(vector<int> &candidates,int start,int target,vector<vector<int> > &ret,vector<int> &path) { if(target<0) return; if(target==0) { ret.push_back(path); return; } int i; for(i=start;i<(int)candidates.size();i++) { if(i>start&&candidates[i]==candidates[i-1]) continue; path.push_back(candidates[i]); combination(candidates,i+1,target-candidates[i],ret,path); path.pop_back(); } }};int main(){ Solution s; vector<int> vec={0,0,10,1,2,7,6,1,5}; vector<vector<int> > result=s.combinationSum2(vec,8); for(auto a:result) { for(auto v:a) cout<<v<<" "; cout<<endl; }}
运行结果：
Combination Sum II
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