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Problem 2082 过路费树链剖分

裸题直接搞。

#include<iostream>#include<cstdio>#include<cstring>#include<map>#include<vector>#include<stdlib.h>using namespace std;#define lson l,mid,rt<<1#define rson mid+1,r,rt<<1|1typedef long long LL;const LL maxn = 55555;LL head[maxn];LL len, z;struct Node{    LL next; LL to;}e[maxn * 2];LL top[maxn], son[maxn];LL father[maxn];LL size[maxn]; LL pos[maxn];LL deep[maxn];LL sum[maxn << 2];LL edge[maxn][10];void add(LL from, LL to){    e[len].to = to;    e[len].next = head[from];    head[from] = len++;}void init(LL x){    size[x] = 1; son[x] = 0;    for (LL i = head[x]; i != -1; i = e[i].next){        LL cc = e[i].to;        if (father[x] == cc) continue;        father[cc] = x; deep[cc] = deep[x] + 1;        init(cc);        size[x] += size[cc];        if (size[son[x]] < size[cc])son[x] = cc;    }}void dfs(LL x, LL tp){    pos[x] = ++z; top[x] = tp;    if (son[x]) dfs(son[x], tp);    for (LL i = head[x]; i != -1; i = e[i].next){        LL cc = e[i].to;        if (cc == father[x] || cc == son[x]) continue;        dfs(cc, cc);    }}void build(LL l, LL r, LL rt){    sum[rt] = 0;    if (l == r) return;    LL mid = (l + r) >> 1;    build(lson); build(rson);}void up(LL rt){    sum[rt] = sum[rt << 1] + sum[rt << 1 | 1];}void update(LL key, LL ans, LL l, LL r, LL rt){    if (l == r){        sum[rt] = ans; return;    }    LL mid = (l + r) >> 1;    if (key <= mid) update(key, ans, lson);    else update(key, ans, rson);    up(rt);}LL ask(LL L, LL R, LL l, LL r, LL rt){    if (L <= l&&r <= R) return sum[rt];    LL mid = (l + r) >> 1;    LL ans = 0;    if (L <= mid) ans += ask(L, R, lson);    if (R > mid) ans += ask(L, R, rson);    return ans;}LL gao(LL x, LL y){    LL ans = 0;    LL fx = top[x]; LL fy = top[y];    while (fx != fy){        if (deep[fx] < deep[fy]){            swap(x, y); swap(fx, fy);        }        ans += ask(pos[fx], pos[x], 1, z, 1);        x = father[fx]; fx = top[x];    }    if (x == y) return ans;    if (deep[x]>deep[y]) swap(x, y);    ans += ask(pos[son[x]], pos[y], 1, z, 1);    return ans;}int main(){    LL a, b, c;    LL n, m;    while (cin >> n >> m){        memset(head, -1, sizeof(head));        len = 0; z = 0;        for (LL i = 1; i < n; i++){            scanf("%I64d%I64d%I64d", &edge[i][0], &edge[i][1], &edge[i][2]);            add(edge[i][0], edge[i][1]); add(edge[i][1], edge[i][0]);        }        deep[1] = 1;        init(1); dfs(1, 1); build(1, z, 1);        for (LL i = 1; i < n; i++){            LL a = edge[i][0]; LL b = edge[i][1]; LL c = edge[i][2];            if (deep[a]>deep[b]) swap(edge[i][0], edge[i][1]);            update(pos[edge[i][1]], c, 1, z, 1);        }        for (LL i = 0; i < m; i++){            scanf("%I64d%I64d%I64d", &a, &b, &c);            if (a == 0){                edge[b][2] = c;                update(pos[edge[b][1]], c, 1, z, 1);            }            else{                LL t = gao(b, c);                printf("%I64d\n", t);            }        }    }    return 0;}

 

Problem 2082 过路费树链剖分