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perfect-rectangle
https://leetcode.com/problems/perfect-rectangle/// https://discuss.leetcode.com/topic/55944/o-n-log-n-sweep-line-solutionpublic class Solution { public class Column implements Comparable<Column> { int xs; int[] rect; public Column(int xs, int[] rect) { this.xs = xs; this.rect = rect; } public int compareTo(Column that) { if (this.xs != that.xs) { return this.xs - that.xs; } return this.rect[0] - that.rect[0]; } } public boolean isRectangleCover(int[][] rectangles) { PriorityQueue<Column> pq = new PriorityQueue<Column>(); int[] border = {Integer.MAX_VALUE, Integer.MIN_VALUE}; for (int[] rect : rectangles) { Column c1 = new Column(rect[0], rect); Column c2 = new Column(rect[2], rect); pq.add(c1); pq.add(c2); if (rect[1] < border[0]) { border[0] = rect[1]; } if (rect[3] > border[1]) { border[1] = rect[3]; } } TreeSet<int[]> tset = new TreeSet<int[]> (new Comparator<int[]>(){ public int compare(int []rect1, int[]rect2) { if (rect1[3] <= rect2[1]) { return -1; } else if (rect1[1] >= rect2[3]) { return 1; } else { return 0; } } }); int yRange = 0; while (!pq.isEmpty()) { int xs = pq.peek().xs; while (!pq.isEmpty() && pq.peek().xs == xs) { Column col = pq.poll(); int[] rect = col.rect; if (xs == rect[2]) { tset.remove(rect); yRange -= rect[3] - rect[1]; } else { // xs == rect[0] if (!tset.add(rect)) { // intersect return false; } yRange += rect[3] - rect[1]; } } // if pq.isEmpty(), the right line, no need to check if (!pq.isEmpty() && yRange != border[1] - border[0]) { return false; } } return true; }}
perfect-rectangle
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